1)
President
Garfield’s Proof of the Pythagorean Theorem
References:
Loomis, Elisha
S. (1968). The Pythagorean proposition. Washington, DC: National Council of Teachers of
Mathematics.
Multiplication By Infiniti. (2011).
US president garfield’s proof of the Pythagorean theorem. Retrieved from
http://tetrahedral.blogspot.com/2011/04/us-president-garfields-proof-of.html
In the figure shown below, we have taken an arbitrary right triangle
with sides of length a, b, and hypotenuse of length c. We draw a second copy of
this same triangle ABC as pictured below.
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First, we need to find the area of the trapezoid by using the area formula of
the trapezoid.
Formula for the area
of a Trapeziod A = ½ h(b1 + b2)
Given the above diagram, h= a + b, b1=a, and b2=b.
Given the above diagram, h= a + b, b1=a, and b2=b.
Using
substitution and the area formula for a trapezoid:
A=½(a+b)(a+b)
A =½(a2+2ab+b2).
A=½(a+b)(a+b)
A =½(a2+2ab+b2).
Now, let's
find the area of the trapezoid by summing the area of the three right triangles.
The area of
the yellow triangle:
Ay = ½ ab
The area of the white triangle:
Aw = ½c2
The area of the blue triangle:
Ab = ½ ab
Ay = ½ ab
The area of the white triangle:
Aw = ½c2
The area of the blue triangle:
Ab = ½ ab
We find the sum of the three triangles:
½ ab + ½c2+ ½ ab = ½ (ab + c2 + ab) = ½ (2ab + c2).
Since the area of the trapezoid equals the sum of the areas of the three triangles, we can set up the following equality:
½(a2
+ 2ab + b2) = ½ (2ab + c2).
Multiplying both sides by 2:
Multiplying both sides by 2:
a2
+ 2ab + b2 = 2ab + c2
And, subtracting 2ab from both
sides:
a2
+ b2 = c2
Thus, we are able to prove the
Pythagorean Theorem.
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